What is the extreme f(x)=-0.020148x^2+0.3862x-1.065 ?

The extreme f(x)=-0.020148x^2+0.3862x-1.065 is Maximum((0.3862)/(0.040296),0.78568…)

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extreme f(x)=-0.020148x^2+0.3862x-1.065

extreme points

f (x) = - 0.020148 x^{2} + 0.3862 x - 1.065

Maximum (\frac{0.3862}{0.040296}, 0.78568 \dots)

Solution steps

f^{'} (x) = - 0.040296 x + 0.3862

Find intervals:

Increasing

: - \infty < x < \frac{0.3862}{0.040296},

Decreasing

: \frac{0.3862}{0.040296} < x < \infty

Plug

x = \frac{0.3862}{0.040296}

into

- 0.020148 x^{2} + 0.3862 x - 1.065 : 0.78568 \dots

Maximum (\frac{0.3862}{0.040296}, 0.78568 \dots)

f (x) = x^{3} - 2 x^{2} - 4 x + 3, - 1 \leq x \leq 3

f (x) = - 12 x^{5} + 45 x^{4} + 40 x^{3} - 3

f (x) = 7 x^{2} - 6

f (y) = (- 25 + 2 x) (\frac{45}{2} - x) x

f (x y) = 4 x y^{2} - 2 x^{2} y - x

What is the extreme f(x)=-0.020148x^2+0.3862x-1.065 ?
The extreme f(x)=-0.020148x^2+0.3862x-1.065 is Maximum((0.3862)/(0.040296),0.78568…)