What is the extreme-1/2 e^{-2x}x-11/4 e^{-2x}+C ?

The extreme-1/2 e^{-2x}x-11/4 e^{-2x}+C is Minimum(-5,C-(e^{10})/4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme-1/2 e^{-2x}x-11/4 e^{-2x}+C

extreme points

- \frac{1}{2} e^{- 2 x} x - \frac{11}{4} e^{- 2 x} + C

Minimum (- 5, C - \frac{e ^{10}}{4})

Solution steps

f^{'} (x) = e^{- 2 x} (x + 5)

Find intervals:

Decreasing

: - \infty < x < - 5,

Increasing

: - 5 < x < \infty

Plug

x = - 5

into

- \frac{1}{2} e^{- 2 x} x - \frac{11}{4} e^{- 2 x} + C : C - \frac{e ^{10}}{4}

Minimum (- 5, C - \frac{e ^{10}}{4})

f (x) = 2 x e^{- x^{2}}

f (x) = x^{2} \cdot (x - 3)^{2}

- x^{2} + 4

1512 x - 0.14 x^{3}

- x^{2} - 1

What is the extreme-1/2 e^{-2x}x-11/4 e^{-2x}+C ?
The extreme-1/2 e^{-2x}x-11/4 e^{-2x}+C is Minimum(-5,C-(e^{10})/4)