What is the extreme f(x)=395x^2-2920x^3 ?

The extreme f(x)=395x^2-2920x^3 is Minimum(0,0),Maximum(79/876 , 2465195/2302128)

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extreme f(x)=395x^2-2920x^3

extreme points

f (x) = 395 x^{2} - 2920 x^{3}

Minimum (0, 0), Maximum (\frac{79}{876}, \frac{2465195}{2302128})

Solution steps

f^{'} (x) = 790 x - 8760 x^{2}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \frac{79}{876},

Decreasing

: \frac{79}{876} < x < \infty

Plug

x = 0

into

395 x^{2} - 2920 x^{3} : 0

Minimum (0, 0)

Plug

x = \frac{79}{876}

into

395 x^{2} - 2920 x^{3} : \frac{2465195}{2302128}

Maximum (\frac{79}{876}, \frac{2465195}{2302128})

Minimum (0, 0), Maximum (\frac{79}{876}, \frac{2465195}{2302128})

f (x) = 4 x e^{- 0.2 x}

f (x) = 6

y = x (x + 2)^{2}

- 0.1 t^{2} 0.8 t + 98.8, 0 \leq t \geq 8

f (x) = 4 x^{2} + x y + 252 x + 4 y^{2} - 252 y

What is the extreme f(x)=395x^2-2920x^3 ?
The extreme f(x)=395x^2-2920x^3 is Minimum(0,0),Maximum(79/876 , 2465195/2302128)