What is the extreme f(x)=-1.872x^2+33.792-102.353 ?

The extreme f(x)=-1.872x^2+33.792-102.353 is Maximum(0,-68.561)

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extreme f(x)=-1.872x^2+33.792-102.353

extreme points

f (x) = - 1.872 x^{2} + 33.792 - 102.353

Maximum (0, - 68.561)

Solution steps

f^{'} (x) = - 3.744 x

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < \infty

Plug

x = 0

into

- 1.872 x^{2} + 33.792 - 102.353 : - 68.561

Maximum (0, - 68.561)

f (x) = cos^{(2)} (x) - 2 sin (x)

x^{3} + y^{4} - 9 x - 16 y^{2}

f (x, y) = e^{x y - 2} + (x - 1) y

y = x - 1 - z + 1

f (x) = x^{3} - 3 x^{2} - 9 x + 1, (0, 5)

What is the extreme f(x)=-1.872x^2+33.792-102.353 ?
The extreme f(x)=-1.872x^2+33.792-102.353 is Maximum(0,-68.561)