What is the extreme f(x)x^3-6x^2+9x+1 ?

The extreme f(x)x^3-6x^2+9x+1 is None

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extreme f(x)x^3-6x^2+9x+1

extreme points

f (x) x^{3} - 6 x^{2} + 9 x + 1

None

Solution steps

Find the critical points:

None

f x x^{3} - 6 x^{2} + 9 x + 1

has no critical points, therefore there are no extreme points

None

f (x, y) = 9 - x^{2} - y^{2} - 4 y^{2}

- 0.02 x^{2} + 1.6 x + 98.2

9 x^{3} - 54 x^{2} + 81 x + 13, - 6 \leq x \leq 2

f (x) = \frac{( x ^{2} - 121 )}{2 x ^{2}}

\frac{( x ^{2} + 16 )}{( x - 3 )}