What is the extreme f(x)=-3sin^2(x) ?

The extreme f(x)=-3sin^2(x) is Maximum(pin,0),Minimum(pi/2+pin,-3)

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extreme f(x)=-3sin^2(x)

extreme points

f (x) = - 3 sin^{2} (x)

Maximum (πn, 0), Minimum (\frac{π}{2} + πn, - 3)

Solution steps

Find the critical points:

x = πn, x = \frac{π}{2} + πn

Domain of

- 3 sin^{2} (x) : - \infty < x < \infty

Find intervals:

Decreasing

: πn < x < \frac{π}{2} + πn,

Increasing

: \frac{π}{2} + πn < x < π + πn

Plug the extreme point

x = πn

into

- 3 sin^{2} (x) \Rightarrow y = 0

Maximum (πn, 0)

Plug the extreme point

x = \frac{π}{2} + πn

into

- 3 sin^{2} (x) \Rightarrow y = - 3

Minimum (\frac{π}{2} + πn, - 3)

Maximum (πn, 0), Minimum (\frac{π}{2} + πn, - 3)

f (x) = f (x) = 9 x^{8} + 8 x^{7} - 8 x - 11

f (x) = 3 x^{2} + 12 x y + 9 y^{2} + y^{3}

f (x) = 6 x^{2} + 2, 1 \leq x \leq 2

f (x) = x^{4} + 2 x^{2} + 1

f (y) = 20.85 x y + 10.7 x^{2} + 51.75 y^{2}

What is the extreme f(x)=-3sin^2(x) ?
The extreme f(x)=-3sin^2(x) is Maximum(pin,0),Minimum(pi/2+pin,-3)