What is the extreme f(x)=x^3-2x^2-15x+5(2.2) ?

The extreme f(x)=x^3-2x^2-15x+5(2.2) is Maximum(-5/3 ,25.81481…),Minimum(3,-25)

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extreme f(x)=x^3-2x^2-15x+5(2.2)

extreme points

f (x) = x^{3} - 2 x^{2} - 15 x + 5 (2.2)

Maximum (- \frac{5}{3}, 25.81481 \dots), Minimum (3, - 25)

Solution steps

f^{'} (x) = 3 x^{2} - 4 x - 15

Find intervals:

Increasing

: - \infty < x < - \frac{5}{3},

Decreasing

: - \frac{5}{3} < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - \frac{5}{3}

into

x^{3} - 2 x^{2} - 15 x + 52.2 : 25.81481 \dots

Maximum (- \frac{5}{3}, 25.81481 \dots)

Plug

x = 3

into

x^{3} - 2 x^{2} - 15 x + 52.2 : - 25

Minimum (3, - 25)

Maximum (- \frac{5}{3}, 25.81481 \dots), Minimum (3, - 25)

f (x, y) = y^{3} - 2 y x - x y^{2} + 2 x^{2}

b - sin (x)

f (x) = x^{3} + 15 x - 2

f (x) = x^{4} + 2 x^{3} + 1 x^{2} + 1 x + 1

y = x^{2} - 3 x

What is the extreme f(x)=x^3-2x^2-15x+5(2.2) ?
The extreme f(x)=x^3-2x^2-15x+5(2.2) is Maximum(-5/3 ,25.81481…),Minimum(3,-25)