What is the extreme f(x)=2x^3+4x^2-1 ?

The extreme f(x)=2x^3+4x^2-1 is Maximum(-4/3 , 37/27),Minimum(0,-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=2x^3+4x^2-1

extreme points

f (x) = 2 x^{3} + 4 x^{2} - 1

Maximum (- \frac{4}{3}, \frac{37}{27}), Minimum (0, - 1)

Solution steps

f^{'} (x) = 6 x^{2} + 8 x

Find intervals:

Increasing

: - \infty < x < - \frac{4}{3},

Decreasing

: - \frac{4}{3} < x < 0,

Increasing

: 0 < x < \infty

Plug

x = - \frac{4}{3}

into

2 x^{3} + 4 x^{2} - 1 : \frac{37}{27}

Maximum (- \frac{4}{3}, \frac{37}{27})

Plug

x = 0

into

2 x^{3} + 4 x^{2} - 1 : - 1

Minimum (0, - 1)

Maximum (- \frac{4}{3}, \frac{37}{27}), Minimum (0, - 1)

49 x + \frac{1}{x}

f (x) = - 0.1 x^{2} + 1.2 x + 5

7 (x - 8)^{3}

y = \frac{x ^{2} - 5}{x - 3}

e^{20 (e^{t} - 1) - 25 t}

What is the extreme f(x)=2x^3+4x^2-1 ?
The extreme f(x)=2x^3+4x^2-1 is Maximum(-4/3 , 37/27),Minimum(0,-1)