What is the extreme f(x)=-0.1t^2+1.4t+98.5 ?

The extreme f(x)=-0.1t^2+1.4t+98.5 is Maximum(7,103.4)

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extreme f(x)=-0.1t^2+1.4t+98.5

extreme points

f (x) = - 0.1 t^{2} + 1.4 t + 98.5

Maximum (7, 103.4)

Solution steps

f^{'} (t) = - 0.2 t + 1.4

Find intervals:

Increasing

: - \infty < t < 7,

Decreasing

: 7 < t < \infty

Plug

t = 7

into

- 0.1 t^{2} + 1.4 t + 98.5 : 103.4

Maximum (7, 103.4)

f (x) = 3 x^{2} - 8 x^{3} + 6 x^{2} + 3

f (x) = - e^{(a (4 - x))} + 1

Z (x, y) = x + y - (\frac{x \cdot y}{100})

sin (θ) - 3 cos (θ)

f (x, y) = (- x^{2} - y^{2} + 2 y - 1)

What is the extreme f(x)=-0.1t^2+1.4t+98.5 ?
The extreme f(x)=-0.1t^2+1.4t+98.5 is Maximum(7,103.4)