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Popular >

extreme y= x/(sqrt(x^2+3))

Solution

extreme points

y = \frac{x}{x ^{2} + 3}

Solution

None

Solution steps

f^{'} (x) = \frac{3}{( x ^{2} + 3 ) x ^{2} + 3}

Find intervals:

None

None

Popular Examples

extreme y=x^2-8x,-infinity <= x<= 8 extreme points

y = x^{2} - 8 x, - \infty \leq x \leq 8

extreme f(x)=28x^{1/2}-x extreme points

f (x) = 28 x^{\frac{1}{2}} - x

extreme f(x)=-27x^2+504x extreme points

f (x) = - 27 x^{2} + 504 x

extreme f(x)=2xsqrt(225-x^2)extreme points

f (x) = 2 x 225 - x^{2}

extreme (x^2+2)/(x^2-9)extreme points

\frac{x ^{2} + 2}{x ^{2} - 9}

Frequently Asked Questions (FAQ)

What is the extreme y= x/(sqrt(x^2+3)) ?
The extreme y= x/(sqrt(x^2+3)) is None