What is the extreme f(x,y)=xy^2-x^2y+x-y ?

The extreme f(x,y)=xy^2-x^2y+x-y is Saddle(1,1),Saddle(-1,-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x,y)=xy^2-x^2y+x-y

extreme points

f (x, y) = x y^{2} - x^{2} y + x - y

Saddle (1, 1), Saddle (- 1, - 1)

Solution steps

Find the critical points:

(1, 1), (- 1, - 1)

\frac{\partial ^{2} f}{\partial x ^{2}} = 2 x

D (x, y) = - 4 x^{2} + 4 x y - 4 y^{2}

Check the sign of at each critical point

Check critical point

(1, 1) :

Saddle

Check critical point

(- 1, - 1) :

Saddle

Saddle (1, 1), Saddle (- 1, - 1)

f (x) = 2 x^{3} + 45 x^{2} - 300, 4 \leq x \leq 11

lo g_{10} (s) (r)

f (x) = x - ln (9 x)

8 x + (\frac{1}{2 x - 1})

\frac{x ^{2} + 5 x + 11}{x - 2}

What is the extreme f(x,y)=xy^2-x^2y+x-y ?
The extreme f(x,y)=xy^2-x^2y+x-y is Saddle(1,1),Saddle(-1,-1)