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Popular >

extreme f(x)=1+(x+1)^2

Solution

extreme points

f (x) = 1 + (x + 1)^{2}

Solution

Minimum (- 1, 1)

Solution steps

f^{'} (x) = 2 x + 2

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < \infty

Plug

x = - 1

into

1 + (x + 1)^{2} : 1

Minimum (- 1, 1)

Popular Examples

extreme 4x^2-2x+11 extreme points

4 x^{2} - 2 x + 11

extreme 6xy-x^3-3y^2 extreme points

6 x y - x^{3} - 3 y^{2}

extreme f(x,y)=2x^2+3y^2-4xy+4x-2y+3 extreme points

f (x, y) = 2 x^{2} + 3 y^{2} - 4 x y + 4 x - 2 y + 3

extreme f(x,y)=sqrt(400-4x^2-36y^2)extreme points

f (x, y) = 400 - 4 x^{2} - 36 y^{2}

extreme e^{x^3-3x}extreme points

e^{x^{3} - 3 x}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=1+(x+1)^2 ?
The extreme f(x)=1+(x+1)^2 is Minimum(-1,1)