What is the extreme f(x)=9+4x^2-x^4 ?

The extreme f(x)=9+4x^2-x^4 is Maximum(-sqrt(2),13),Minimum(0,9),Maximum(sqrt(2),13)

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extreme f(x)=9+4x^2-x^4

extreme points

f (x) = 9 + 4 x^{2} - x^{4}

Maximum (- 2, 13), Minimum (0, 9), Maximum (2, 13)

Solution steps

f^{'} (x) = - 4 x^{3} + 8 x

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 0,

Increasing

: 0 < x < 2,

Decreasing

: 2 < x < \infty

Plug

x = - 2

into

9 + 4 x^{2} - x^{4} : 13

Maximum (- 2, 13)

Plug

x = 0

into

9 + 4 x^{2} - x^{4} : 9

Minimum (0, 9)

Plug

x = 2

into

9 + 4 x^{2} - x^{4} : 13

Maximum (2, 13)

Maximum (- 2, 13), Minimum (0, 9), Maximum (2, 13)

f (x, y) = 3 - x + 2 y

f (x, y) = - 2 x^{3} + 14 x^{2} + 2 y^{2} + 4 x y

\frac{t}{6 + 3}

f (x) = \frac{4860}{x} + 20 x + 726363

4 - x^{2}, - 1 \leq x \leq 2

What is the extreme f(x)=9+4x^2-x^4 ?
The extreme f(x)=9+4x^2-x^4 is Maximum(-sqrt(2),13),Minimum(0,9),Maximum(sqrt(2),13)