What is the extreme f(x)=16x+19x^{16/19} ?

The extreme f(x)=16x+19x^{16/19} is Minimum(-1,3),Maximum(0,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=16x+19x^{16/19}

extreme points

f (x) = 16 x + 19 x^{\frac{16}{19}}

Minimum (- 1, 3), Maximum (0, 0)

Solution steps

f^{'} (x) = 16 + \frac{16}{x ^{\frac{3}{19}}}

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < \infty

Plug

x = - 1

into

16 x + 19 x^{\frac{16}{19}} : 3

Minimum (- 1, 3)

Plug

x = 0

into

16 x + 19 x^{\frac{16}{19}} : 0

Maximum (0, 0)

Minimum (- 1, 3), Maximum (0, 0)

f (t) = t^{2} + \frac{1}{t}

y = \frac{1}{3} x^{3} + 2 x^{2} + 3 x

f (x) = y \cdot (e^{x} - 1)

f (x, y) = 2 x^{2} + 8 x - 3 y^{2} + 24 y + 7

f (x) = 2 x^{3} - 6 x^{2} - 48 x

What is the extreme f(x)=16x+19x^{16/19} ?
The extreme f(x)=16x+19x^{16/19} is Minimum(-1,3),Maximum(0,0)