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Popular >

extreme f(y)=2x^2-9x+5

Solution

extreme points

f (y) = 2 x^{2} - 9 x + 5

Solution

Minimum (\frac{9}{4}, - \frac{41}{8})

Solution steps

f^{'} (x) = 4 x - 9

Find intervals:

Decreasing

: - \infty < x < \frac{9}{4},

Increasing

: \frac{9}{4} < x < \infty

Plug

x = \frac{9}{4}

into

2 x^{2} - 9 x + 5 : - \frac{41}{8}

Minimum (\frac{9}{4}, - \frac{41}{8})

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Frequently Asked Questions (FAQ)

What is the extreme f(y)=2x^2-9x+5 ?
The extreme f(y)=2x^2-9x+5 is Minimum(9/4 ,-41/8)