What is the extreme f(x)=((5x^2))/(ln(x)) ?

The extreme f(x)=((5x^2))/(ln(x)) is Minimum(sqrt(e),10e)

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extreme f(x)=((5x^2))/(ln(x))

extreme points

f (x) = \frac{( 5 x ^{2} )}{ln ( x )}

Minimum (e, 10 e)

Solution steps

f^{'} (x) = \frac{5 ( 2 x ln ( x ) - x )}{ln ^{2} ( x )}

Find intervals:

Decreasing

: 0 < x < 1,

Decreasing

: 1 < x < e,

Increasing

: e < x < \infty

Plug

x = e

into

\frac{5 x ^{2}}{ln ( x )} : 10 e

Minimum (e, 10 e)

f (x) = x^{3} - 2 x^{2} + 14

f (x) = x^{3} - 2 x^{2} + 10

f (x) = - 4 \cdot x^{2} \cdot y + 4 \cdot x \cdot y^{2}

x^{3} - 3 x^{2} - 5 x - 5

f (x) = \frac{1}{3} x^{3} + \frac{1}{2} x^{2} - 2 x + 1

What is the extreme f(x)=((5x^2))/(ln(x)) ?
The extreme f(x)=((5x^2))/(ln(x)) is Minimum(sqrt(e),10e)