What is the extreme y=-2cos(x) ?

The extreme y=-2cos(x) is Minimum(2pin,-2),Maximum(pi+2pin,2)

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extreme y=-2cos(x)

extreme points

y = - 2 cos (x)

Minimum (2 πn, - 2), Maximum (π + 2 πn, 2)

Solution steps

Find the critical points:

x = 2 πn, x = π + 2 πn

Domain of

- 2 cos (x) : - \infty < x < \infty

Find intervals:

Increasing

: 2 πn < x < π + 2 πn,

Decreasing

: π + 2 πn < x < 2 π + 2 πn

Plug the extreme point

x = 2 πn

into

- 2 cos (x) \Rightarrow y = - 2

Minimum (2 πn, - 2)

Plug the extreme point

x = π + 2 πn

into

- 2 cos (x) \Rightarrow y = 2

Maximum (π + 2 πn, 2)

Minimum (2 πn, - 2), Maximum (π + 2 πn, 2)

f (x, y) = 2 - x^{2} - 3 y^{2}

f (x y) = 2 x y^{3} - 2 x^{2} y

f (x) = e^{6 x^{2} + 5 y^{2} + 7}

f (x) = x^{2} + x y + y^{2} - 9 x + 7

f (h) = 200 h^{\frac{2}{3}} s^{\frac{1}{3}}

What is the extreme y=-2cos(x) ?
The extreme y=-2cos(x) is Minimum(2pin,-2),Maximum(pi+2pin,2)