What is the extreme y=-x^2+5,(-2,4) ?

The extreme y=-x^2+5,(-2,4) is Maximum(0,5)

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extreme y=-x^2+5,(-2,4)

extreme points

y = - x^{2} + 5, (- 2, 4)

Maximum (0, 5)

Solution steps

Find the critical points:

x = 0

Domain of

- x^{2} + 5, (- 2, 4) : - 2 < x < 4

Find intervals:

Increasing

: - 2 < x < 0,

Decreasing

: 0 < x < 4

Plug the extreme point

x = 0

into

- x^{2} + 5 \Rightarrow y = 5

Maximum (0, 5)

f (x) = 4 sin (x) + 3 cos (x)

f (x y) = x^{2} + y^{2} + x + y + x y

f (x, y) = y e^{x^{2} - 2 y^{2}}

f (x) = x^{2} + x y + 12 y^{2} - 4 x + y

f (x, y) = 6 x + 6 x y + y

What is the extreme y=-x^2+5,(-2,4) ?
The extreme y=-x^2+5,(-2,4) is Maximum(0,5)