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Popular >

extreme f(x)=-(15)/(x^2+3)

Solution

extreme points

f (x) = - \frac{15}{x ^{2} + 3}

Solution

Minimum (0, - 5)

Solution steps

f^{'} (x) = \frac{30 x}{( x ^{2} + 3 ) ^{2}}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

- \frac{15}{x ^{2} + 3} : - 5

Minimum (0, - 5)

Popular Examples

extreme x^2-5x+8 extreme points

x^{2} - 5 x + 8

extreme f(y,x)y=(x^3)/3-x^2-24x-8 extreme points

f (y, x) y = \frac{x ^{3}}{3} - x^{2} - 24 x - 8

extreme f(x)=(16x^2+25)/x extreme points

f (x) = \frac{16 x ^{2} + 25}{x}

extreme y=9-x extreme points

y = 9 - x

extreme f(x,y)=2x^2+2xy+3y^2-16x-18y+54 extreme points

f (x, y) = 2 x^{2} + 2 x y + 3 y^{2} - 16 x - 18 y + 54

Frequently Asked Questions (FAQ)

What is the extreme f(x)=-(15)/(x^2+3) ?
The extreme f(x)=-(15)/(x^2+3) is Minimum(0,-5)