What is the extreme f(x)=sqrt(4)+6x^2-x^4-2 ?

The extreme f(x)=sqrt(4)+6x^2-x^4-2 is Maximum(-sqrt(3),9),Minimum(0,0),Maximum(sqrt(3),9)

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extreme f(x)=sqrt(4)+6x^2-x^4-2

extreme points

f (x) = 4 + 6 x^{2} - x^{4} - 2

Maximum (- 3, 9), Minimum (0, 0), Maximum (3, 9)

Solution steps

f^{'} (x) = - 4 x^{3} + 12 x

Find intervals:

Increasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < 0,

Increasing

: 0 < x < 3,

Decreasing

: 3 < x < \infty

Plug

x = - 3

into

4 + 6 x^{2} - x^{4} - 2 : 9

Maximum (- 3, 9)

Plug

x = 0

into

4 + 6 x^{2} - x^{4} - 2 : 0

Minimum (0, 0)

Plug

x = 3

into

4 + 6 x^{2} - x^{4} - 2 : 9

Maximum (3, 9)

Maximum (- 3, 9), Minimum (0, 0), Maximum (3, 9)

f (x) = x^{3} + 12 x^{2} - 27 x + 2, - 10 \leq x \leq 0

P (X, Y) = 30 X + 10 Y

f (x) = \frac{2 e ^{2 x}}{5 x - 15}

f (x) = x^{3} + 12 x^{2} - 27 x + 2, - 10 \leq x \leq 2

f (x) = 200 x - \frac{2}{3} x^{2}

What is the extreme f(x)=sqrt(4)+6x^2-x^4-2 ?
The extreme f(x)=sqrt(4)+6x^2-x^4-2 is Maximum(-sqrt(3),9),Minimum(0,0),Maximum(sqrt(3),9)