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Popular >

extreme f(x)=x^2+5/2

Solution

extreme points

f (x) = x^{2} + \frac{5}{2}

Solution

Minimum (0, \frac{5}{2})

Solution steps

f^{'} (x) = 2 x

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

x^{2} + \frac{5}{2} : \frac{5}{2}

Minimum (0, \frac{5}{2})

Popular Examples

extreme f(x)= 1/(x-8)extreme points

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extreme f(x)=x+6x extreme points

f (x) = x + 6 x

extreme f(x)=3x^3-12x^2+1 extreme points

f (x) = 3 x^{3} - 12 x^{2} + 1

extreme f(x)=(x^2-1)*e^x extreme points

f (x) = (x^{2} - 1) \cdot e^{x}

extreme f(x)=125x^3+15x+7 extreme points

f (x) = 125 x^{3} + 15 x + 7

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2+5/2 ?
The extreme f(x)=x^2+5/2 is Minimum(0, 5/2)