What is the extreme f(x)=3+7x+175x^{-1} ?

The extreme f(x)=3+7x+175x^{-1} is Maximum(-5,-67),Minimum(5,73)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=3+7x+175x^{-1}

extreme points

f (x) = 3 + 7 x + 175 x^{- 1}

Maximum (- 5, - 67), Minimum (5, 73)

Solution steps

f^{'} (x) = - \frac{175}{x ^{2}} + 7

Find intervals:

Increasing

: - \infty < x < - 5,

Decreasing

: - 5 < x < 0,

Decreasing

: 0 < x < 5,

Increasing

: 5 < x < \infty

Plug

x = - 5

into

3 + 7 x + 175 x^{- 1} : - 67

Maximum (- 5, - 67)

Plug

x = 5

into

3 + 7 x + 175 x^{- 1} : 73

Minimum (5, 73)

Maximum (- 5, - 67), Minimum (5, 73)

\frac{1}{x ^{2} - x - 6}

f (x) = - 2 (x - 2)^{3} (x + 2) (x + 4)

f (x) = 4 x^{3} - 46 x^{2} + 120 x

f (x, y) = x^{2} + 3 y^{2}

Q (x, y) = 6 x^{2} + 3 y^{2}

What is the extreme f(x)=3+7x+175x^{-1} ?
The extreme f(x)=3+7x+175x^{-1} is Maximum(-5,-67),Minimum(5,73)