What is the extreme y=x^3-3/2 x^2 ?

The extreme y=x^3-3/2 x^2 is Maximum(0,0),Minimum(1,-1/2)

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extreme y=x^3-3/2 x^2

extreme points

y = x^{3} - \frac{3}{2} x^{2}

Maximum (0, 0), Minimum (1, - \frac{1}{2})

Solution steps

f^{'} (x) = 3 x^{2} - 3 x

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = 0

into

x^{3} - \frac{3}{2} x^{2} : 0

Maximum (0, 0)

Plug

x = 1

into

x^{3} - \frac{3}{2} x^{2} : - \frac{1}{2}

Minimum (1, - \frac{1}{2})

Maximum (0, 0), Minimum (1, - \frac{1}{2})

f (x) = 5 x^{2} - 8 x + 3

f (x) = - x^{3} + 9 x^{2} + 216 x + 4766

f (x) = x + \frac{4}{x}

2 x^{2} - 12 x - 5

x^{\frac{4}{5}} (x^{2} - 7)

What is the extreme y=x^3-3/2 x^2 ?
The extreme y=x^3-3/2 x^2 is Maximum(0,0),Minimum(1,-1/2)