What is the domain of f(x)= 1/((x+3)^2) ?

The domain of f(x)= 1/((x+3)^2) is x -3

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domain of f(x)= 1/((x+3)^2)

domain

f (x) = \frac{1}{( x + 3 ) ^{2}}

x < - 3 or x > - 3

Interval Notation

(- \infty, - 3) \cup (- 3, \infty)

Solution steps

Find undefined (singularity) points:

x = - 3

The function domain

x < - 3 or x > - 3

f (x) = \frac{x ^{2} - 2 x + 1}{x + 1}

f (x) = (x - 10) 3 + 4

x^{3} - 2 x^{2} - 4 x + 6

f (x) = \frac{x ^{2} - 11 x - 24}{x ^{2} - 9}

f (x) = 5 x^{3} + 6 x^{2} - 1

What is the domain of f(x)= 1/((x+3)^2) ?
The domain of f(x)= 1/((x+3)^2) is x<-3\lor x>-3