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Popular >

extreme f(x)=2x^4-8x

Solution

extreme points

f (x) = 2 x^{4} - 8 x

Solution

Minimum (1, - 6)

Solution steps

f^{'} (x) = 8 x^{3} - 8

Find intervals:

Decreasing

: - \infty < x < 1,

Increasing

: 1 < x < \infty

Plug

x = 1

into

2 x^{4} - 8 x : - 6

Minimum (1, - 6)

Popular Examples

extreme 4x^3-12x^2+8x extreme points

4 x^{3} - 12 x^{2} + 8 x

extreme f(x)=6x^2-6x-36 extreme points

f (x) = 6 x^{2} - 6 x - 36

extreme f(x)=((1+x))/(3-x)extreme points

f (x) = \frac{( 1 + x )}{3 - x}

extreme f(x)=3x-100-15/1000 x^2 extreme points

f (x) = 3 x - 100 - \frac{15}{1000} x^{2}

extreme-1/2 x^3-3/2 x^2 extreme points

- \frac{1}{2} x^{3} - \frac{3}{2} x^{2}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=2x^4-8x ?
The extreme f(x)=2x^4-8x is Minimum(1,-6)