What is the extreme f(x)= x/(5x-4),6<= x<= 7 ?

The extreme f(x)= x/(5x-4),6<= x<= 7 is Maximum(6, 3/13),Minimum(7, 7/31)

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extreme f(x)= x/(5x-4),6<= x<= 7

extreme points

f (x) = \frac{x}{5 x - 4}, 6 \leq x \leq 7

Maximum (6, \frac{3}{13}), Minimum (7, \frac{7}{31})

Solution steps

Find the critical points:

x = 6, x = 7

Domain of

\frac{x}{5 x - 4}, 6 \leq x \leq 7 : 6 \leq x \leq 7

Find intervals:

Decreasing

: 6 < x < 7

Plug the extreme point

x = 6

into

\frac{x}{5 x - 4} \Rightarrow y = \frac{3}{13}

Maximum (6, \frac{3}{13})

Plug the extreme point

x = 7

into

\frac{x}{5 x - 4} \Rightarrow y = \frac{7}{31}

Minimum (7, \frac{7}{31})

Maximum (6, \frac{3}{13}), Minimum (7, \frac{7}{31})

f (x) = 4 x^{\frac{10}{3}} - 10 x^{\frac{4}{3}}

f (x) = y - y^{2}

f (x) = 4 x^{2} - 6 x y + 5 y^{2} - 20 x + 26 y

f (x) = - 1.6

f (x) = e^{x + y}

What is the extreme f(x)= x/(5x-4),6<= x<= 7 ?
The extreme f(x)= x/(5x-4),6<= x<= 7 is Maximum(6, 3/13),Minimum(7, 7/31)