What is the extreme f(x)=12x^2-180x+464 ?

The extreme f(x)=12x^2-180x+464 is Minimum(15/2 ,-211)

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extreme f(x)=12x^2-180x+464

extreme points

f (x) = 12 x^{2} - 180 x + 464

Minimum (\frac{15}{2}, - 211)

Solution steps

f^{'} (x) = 24 x - 180

Find intervals:

Decreasing

: - \infty < x < \frac{15}{2},

Increasing

: \frac{15}{2} < x < \infty

Plug

x = \frac{15}{2}

into

12 x^{2} - 180 x + 464 : - 211

Minimum (\frac{15}{2}, - 211)

f (x) = - \frac{3}{16} x^{\frac{8}{3}} + \frac{3}{4} x^{\frac{2}{3}}

2 sin (x) - cos (x) - 4 x

\frac{x ^{2} - 3 x - 10}{x + 6}, - 2 \leq x \leq 5

f (x) = 300 x - x^{2}

y = x^{3} - 2 x^{2} + x + 1

What is the extreme f(x)=12x^2-180x+464 ?
The extreme f(x)=12x^2-180x+464 is Minimum(15/2 ,-211)