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Popular >

extreme f(x)=-4x^2+4x-3

Solution

extreme points

f (x) = - 4 x^{2} + 4 x - 3

Solution

Maximum (\frac{1}{2}, - 2)

Solution steps

f^{'} (x) = - 8 x + 4

Find intervals:

Increasing

: - \infty < x < \frac{1}{2},

Decreasing

: \frac{1}{2} < x < \infty

Plug

x = \frac{1}{2}

into

- 4 x^{2} + 4 x - 3 : - 2

Maximum (\frac{1}{2}, - 2)

Popular Examples

extreme f(x)=x^2log_{10}(2x)extreme points

f (x) = x^{2} lo g_{10} (2 x)

extreme f(x)=-[x+2]extreme points

f (x) = - [x + 2]

extreme f(x)=2x^3+9x^2-24x,-5<= x<= 2 extreme points

f (x) = 2 x^{3} + 9 x^{2} - 24 x, - 5 \leq x \leq 2

extreme 22x^2 extreme points

22 x^{2}

extreme f(x)=(x^3-1)^4,-1<= x<= 2 extreme points

f (x) = (x^{3} - 1)^{4}, - 1 \leq x \leq 2

Frequently Asked Questions (FAQ)

What is the extreme f(x)=-4x^2+4x-3 ?
The extreme f(x)=-4x^2+4x-3 is Maximum(1/2 ,-2)