What is the extreme f(x)=x^3-12x^2-27x+9(-2) ?

The extreme f(x)=x^3-12x^2-27x+9(-2) is Maximum(-1,-4),Minimum(9,-504)

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extreme f(x)=x^3-12x^2-27x+9(-2)

extreme points

f (x) = x^{3} - 12 x^{2} - 27 x + 9 (- 2)

Maximum (- 1, - 4), Minimum (9, - 504)

Solution steps

f^{'} (x) = 3 x^{2} - 24 x - 27

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 9,

Increasing

: 9 < x < \infty

Plug

x = - 1

into

x^{3} - 12 x^{2} - 27 x + 9 (- 2) : - 4

Maximum (- 1, - 4)

Plug

x = 9

into

x^{3} - 12 x^{2} - 27 x + 9 (- 2) : - 504

Minimum (9, - 504)

Maximum (- 1, - 4), Minimum (9, - 504)

f (x) = 13 + 7 x + x^{2}

x^{\frac{1}{3}} (x + 4), - 27 \leq x \leq 27

f (x) = 1 + 4 x - 5 y

f (x) = - 2 x + 5 ln (2 x), (1, 5)

f (x) = \frac{x + 4}{x - 2}

What is the extreme f(x)=x^3-12x^2-27x+9(-2) ?
The extreme f(x)=x^3-12x^2-27x+9(-2) is Maximum(-1,-4),Minimum(9,-504)