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Popular >

extreme f(x)=(x^2+4)^2

Solution

extreme points

f (x) = (x^{2} + 4)^{2}

Solution

Minimum (0, 16)

Solution steps

f^{'} (x) = 4 x (x^{2} + 4)

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

(x^{2} + 4)^{2} : 16

Minimum (0, 16)

Popular Examples

extreme f(x)=9x^2-72x+108 extreme points

f (x) = 9 x^{2} - 72 x + 108

extreme x^4+3x^3-6 extreme points

x^{4} + 3 x^{3} - 6

extreme f(x,y)=x^2-14x+y^2-16y extreme points

f (x, y) = x^{2} - 14 x + y^{2} - 16 y

extreme f(x)=x^3-5x+4 extreme points

f (x) = x^{3} - 5 x + 4

extreme f(x)=8x+4 extreme points

f (x) = 8 x + 4

Frequently Asked Questions (FAQ)

What is the extreme f(x)=(x^2+4)^2 ?
The extreme f(x)=(x^2+4)^2 is Minimum(0,16)