What is the extreme f(x)=x^2-xy+y^2 ?

The extreme f(x)=x^2-xy+y^2 is Minimum(0,0)

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extreme f(x)=x^2-xy+y^2

extreme points

f (x) = x^{2} - x y + y^{2}

Minimum (0, 0)

Solution steps

Find the critical points:

(0, 0)

\frac{\partial ^{2} f}{\partial x ^{2}} = 2

D (x, y) = 3

Check the sign of at each critical point

Check critical point

(0, 0) :

Minimum

Minimum (0, 0)

5 x - 3

f (x) = - x^{3} + 3 x^{2} + 2 x

8 x^{6} - 13 x^{5}

f (x, y) = x y^{2} - x^{2} y

f (x, y) = y - e - 2 x^{2} y

What is the extreme f(x)=x^2-xy+y^2 ?
The extreme f(x)=x^2-xy+y^2 is Minimum(0,0)