What is the extreme f(x)=(x^3)/3-5/2 x^2+4x+3 ?

The extreme f(x)=(x^3)/3-5/2 x^2+4x+3 is Maximum(1, 29/6),Minimum(4, 1/3)

Popular >

extreme f(x)=(x^3)/3-5/2 x^2+4x+3

extreme points

f (x) = \frac{x ^{3}}{3} - \frac{5}{2} x^{2} + 4 x + 3

Maximum (1, \frac{29}{6}), Minimum (4, \frac{1}{3})

Solution steps

f^{'} (x) = x^{2} - 5 x + 4

Find intervals:

Increasing

: - \infty < x < 1,

Decreasing

: 1 < x < 4,

Increasing

: 4 < x < \infty

Plug

x = 1

into

\frac{x ^{3}}{3} - \frac{5}{2} x^{2} + 4 x + 3 : \frac{29}{6}

Maximum (1, \frac{29}{6})

Plug

x = 4

into

\frac{x ^{3}}{3} - \frac{5}{2} x^{2} + 4 x + 3 : \frac{1}{3}

Minimum (4, \frac{1}{3})

Maximum (1, \frac{29}{6}), Minimum (4, \frac{1}{3})

f (x) = 0.502994 x + 2.67066

36 x y - x^{3} - 8 y^{3}

f (x) = x^{2} = 4 a y

f (x) = (\frac{5 ^{2} - x ^{2}}{x})^{2}

What is the extreme f(x)=(x^3)/3-5/2 x^2+4x+3 ?
The extreme f(x)=(x^3)/3-5/2 x^2+4x+3 is Maximum(1, 29/6),Minimum(4, 1/3)