What is the extreme (20)/r+5pir^2 ?

The extreme (20)/r+5pir^2 is Minimum(\sqrt[3]{2/pi},10*2^{2/3}\sqrt[3]{pi}+5pi(2/pi)^{2/3})

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extreme (20)/r+5pir^2

extreme points

\frac{20}{r} + 5 π r^{2}

Solution steps

f^{'} (r) = - \frac{20}{r ^{2}} + 10 π r

Find intervals:

Decreasing

: - \infty < r < 0,

Decreasing

Increasing

Plug

into

f (x, y) = - 4 x^{2} - 3 x y - 2 y^{2} + 66 x + 19 y + 5

f (x) = x (x + 3)^{\frac{1}{2}}

f (x, y) = 2 x + 4 y - x^{2} - y^{2} - 3

f (x) = 4 x^{3} - 36 x^{2} + 80 x

2 x - 4

What is the extreme (20)/r+5pir^2 ?
The extreme (20)/r+5pir^2 is Minimum(\sqrt[3]{2/pi},10*2^{2/3}\sqrt[3]{pi}+5pi(2/pi)^{2/3})