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Popular >

extreme sqrt(x^2+4x)

Solution

extreme points

x^{2} + 4 x

Solution

Minimum (- 4, 0), Minimum (0, 0)

Solution steps

f^{'} (x) = \frac{x + 2}{x ^{2} + 4 x}

Find intervals:

Decreasing

: - \infty < x < - 4,

Increasing

: 0 < x < \infty

Plug

x = - 4

into

x^{2} + 4 x : 0

Minimum (- 4, 0)

Plug

x = 0

into

x^{2} + 4 x : 0

Minimum (0, 0)

Minimum (- 4, 0), Minimum (0, 0)

Popular Examples

extreme 4x^2-4(8-x)^2 extreme points

4 x^{2} - 4 (8 - x)^{2}

extreme f(x)=3x-10sin(x/3),10<= x<= 38 extreme points

f (x) = 3 x - 10 sin (\frac{x}{3}), 1 0^{\circ} \leq x \leq 3 8^{\circ}

extreme f(x)=9x+3/x extreme points

f (x) = 9 x + \frac{3}{x}

extreme f(x,y)=x^2+y^2-16x+20y-5 extreme points

f (x, y) = x^{2} + y^{2} - 16 x + 20 y - 5

extreme f(x)=4x^4 extreme points

f (x) = 4 x^{4}

Frequently Asked Questions (FAQ)

What is the extreme sqrt(x^2+4x) ?
The extreme sqrt(x^2+4x) is Minimum(-4,0),Minimum(0,0)