What is the extreme f(x)=-x^3-9x^2+4 ?

The extreme f(x)=-x^3-9x^2+4 is Minimum(-6,-104),Maximum(0,4)

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extreme f(x)=-x^3-9x^2+4

extreme points

f (x) = - x^{3} - 9 x^{2} + 4

Minimum (- 6, - 104), Maximum (0, 4)

Solution steps

f^{'} (x) = - 3 x^{2} - 18 x

Find intervals:

Decreasing

: - \infty < x < - 6,

Increasing

: - 6 < x < 0,

Decreasing

: 0 < x < \infty

Plug

x = - 6

into

- x^{3} - 9 x^{2} + 4 : - 104

Minimum (- 6, - 104)

Plug

x = 0

into

- x^{3} - 9 x^{2} + 4 : 4

Maximum (0, 4)

Minimum (- 6, - 104), Maximum (0, 4)

x^{2} + 1 + e^{x y}

f (x, y) = y + 81 - x^{2} - y^{2}

f (x) = \frac{2 x ^{3}}{3} + \frac{7 x ^{2}}{2} - 4 x

f (x) = \frac{1}{3} x^{3} - \frac{1}{2} x^{2} - 2 x + \frac{4}{3}

- 3 sin (2 x) - 4

What is the extreme f(x)=-x^3-9x^2+4 ?
The extreme f(x)=-x^3-9x^2+4 is Minimum(-6,-104),Maximum(0,4)