What is the extreme f(x)=x^4-4x^3-8 ?

The extreme f(x)=x^4-4x^3-8 is Saddle(0,-8),Minimum(3,-35)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=x^4-4x^3-8

extreme points

f (x) = x^{4} - 4 x^{3} - 8

Saddle (0, - 8), Minimum (3, - 35)

Solution steps

f^{'} (x) = 4 x^{3} - 12 x^{2}

Find intervals:

Decreasing

: - \infty < x < 0,

Decreasing

: 0 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = 0

into

x^{4} - 4 x^{3} - 8 : - 8

Saddle (0, - 8)

Plug

x = 3

into

x^{4} - 4 x^{3} - 8 : - 35

Minimum (3, - 35)

Saddle (0, - 8), Minimum (3, - 35)

x, f = x^{2} - 4 x y + y^{2}

f (x) = x^{\frac{2}{5}} (3 x + 7)

x^{3} - 2 x^{2} - 15 x + 10 [- 2.1]

f (x) = x + \frac{9}{x} + 2

f (x, y) = x^{3} + y^{3} - 3 x - 12 y + 30

What is the extreme f(x)=x^4-4x^3-8 ?
The extreme f(x)=x^4-4x^3-8 is Saddle(0,-8),Minimum(3,-35)