What is the extreme f(x)=x^4-8x+4 ?

The extreme f(x)=x^4-8x+4 is Minimum(\sqrt[3]{2},-6\sqrt[3]{2}+4)

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extreme f(x)=x^4-8x+4

extreme points

f (x) = x^{4} - 8 x + 4

Solution steps

f^{'} (x) = 4 x^{3} - 8

Find intervals:

Decreasing

Increasing

Plug

into

x^{2} y + 2 x y - y^{2} - 3 y

f (x, y) = 2 x^{2} + x y + 4 y^{2} - 2 x + 10 y

f (x) = x^{3} - 6 x^{2} - 9 x - 2

f (x) = x \cdot 500 - x

f (x) = - 8 x^{2} + x^{4}

What is the extreme f(x)=x^4-8x+4 ?
The extreme f(x)=x^4-8x+4 is Minimum(\sqrt[3]{2},-6\sqrt[3]{2}+4)