What is the extreme f(x)=ln(x),0<x<= 4 ?

The extreme f(x)=ln(x),0<x<= 4 is Maximum(4,2ln(2))

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extreme f(x)=ln(x),0<x<= 4

extreme points

f (x) = ln (x), 0 < x \leq 4

Maximum (4, 2 ln (2))

Solution steps

Find the critical points:

x = 4

Domain of

ln (x), 0 < x \leq 4 : 0 < x \leq 4

Find intervals:

Increasing

: 0 < x < 4

Plug the extreme point

x = 4

into

ln (x) \Rightarrow y = 2 ln (2)

Maximum (4, 2 ln (2))

f (x, y) = e - (x^{2} + y^{2} - 6 y)

2 x^{3} + 6 x^{2} - 48 x

f (x) = - 2 x^{2} - 20 x + 8

f (x) = x^{5} - x^{3} + 1

y = \frac{x}{x ^{2} + 16}

What is the extreme f(x)=ln(x),0<x<= 4 ?
The extreme f(x)=ln(x),0<x<= 4 is Maximum(4,2ln(2))