What is the extreme f(x)=sqrt(420-x)x ?

The extreme f(x)=sqrt(420-x)x is Maximum(280,560sqrt(35)),Minimum(420,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=sqrt(420-x)x

extreme points

f (x) = 420 - x x

Maximum (280, 56035), Minimum (420, 0)

Solution steps

f^{'} (x) = - \frac{3 ( x - 280 )}{2 420 - x}

Find intervals:

Increasing

: - \infty < x < 280,

Decreasing

: 280 < x < 420

Plug

x = 280

into

420 - x x : 56035

Maximum (280, 56035)

Plug

x = 420

into

420 - x x : 0

Minimum (420, 0)

Maximum (280, 56035), Minimum (420, 0)

f (x) = 3 x^{2} - 10 x - 25

S (x, y) = 3 x - 2 y + (3 x - 5 y) - 2 x + [3 y - (2 x - 7 y) + 4 x]

f (x) = 5 - 5 x + x^{2}

P (x, y) = m^{2} x m + 3 y m + 7 - m^{3} x m + 7 y m + 4 + m x m + 8 y m + 6

x^{2} - 5 a^{2}

What is the extreme f(x)=sqrt(420-x)x ?
The extreme f(x)=sqrt(420-x)x is Maximum(280,560sqrt(35)),Minimum(420,0)