What is the extreme f(x,y)=-25x^2-25y^2+300x+350y+190 ?

The extreme f(x,y)=-25x^2-25y^2+300x+350y+190 is Maximum(6,7)

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extreme f(x,y)=-25x^2-25y^2+300x+350y+190

extreme points

f (x, y) = - 25 x^{2} - 25 y^{2} + 300 x + 350 y + 190

Maximum (6, 7)

Solution steps

Find the critical points:

(6, 7)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 50

D (x, y) = 2500

Check the sign of at each critical point

Check critical point

(6, 7) :

Maximum

Maximum (6, 7)

f (x, y) = x^{2} - 2 x y + 2 y^{2} x

f (x) = 56 - 18 x + 3 x^{2}

f (x) = 3 + 4 x^{2} - x^{4}

y = \frac{1}{3} x^{3} - \frac{5}{2} x^{2} + 6 x - 2

f (x, y) = x^{2} - 2 x y - 3 x + 6

What is the extreme f(x,y)=-25x^2-25y^2+300x+350y+190 ?
The extreme f(x,y)=-25x^2-25y^2+300x+350y+190 is Maximum(6,7)