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Popular >

extreme (t^2)/(t+3)

Solution

extreme points

\frac{t ^{2}}{t + 3}

Solution

Maximum (- 6, - 12), Minimum (0, 0)

Solution steps

f^{'} (t) = \frac{t ^{2} + 6 t}{( t + 3 ) ^{2}}

Find intervals:

Increasing

: - \infty < t < - 6,

Decreasing

: - 6 < t < - 3,

Decreasing

: - 3 < t < 0,

Increasing

: 0 < t < \infty

Plug

t = - 6

into

\frac{t ^{2}}{t + 3} : - 12

Maximum (- 6, - 12)

Plug

t = 0

into

\frac{t ^{2}}{t + 3} : 0

Minimum (0, 0)

Maximum (- 6, - 12), Minimum (0, 0)

Popular Examples

extreme f(x)=x^3-10x+25x-2 extreme points

f (x) = x^{3} - 10 x + 25 x - 2

extreme f(x)=(20)/x+2pix^2,x>0 extreme points

f (x) = \frac{20}{x} + 2 π x^{2}, x > 0

extreme f(x)=-x^3+x^2+11x-1 extreme points

f (x) = - x^{3} + x^{2} + 11 x - 1

extreme f(x)=2x-sin(x)extreme points

f (x) = 2 x - sin (x)

extreme f(x)=(x^2)/(1+x),-1/2 <= x<= 1 extreme points

f (x) = \frac{x ^{2}}{1 + x}, - \frac{1}{2} \leq x \leq 1

Frequently Asked Questions (FAQ)

What is the extreme (t^2)/(t+3) ?
The extreme (t^2)/(t+3) is Maximum(-6,-12),Minimum(0,0)