What is the extreme f(x)=(x^2)/(144)-(y^2)/(81) ?

The extreme f(x)=(x^2)/(144)-(y^2)/(81) is Saddle(0,0)

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extreme f(x)=(x^2)/(144)-(y^2)/(81)

extreme points

f (x) = \frac{x ^{2}}{144} - \frac{y ^{2}}{81}

Saddle (0, 0)

Solution steps

Find the critical points:

(0, 0)

\frac{\partial ^{2} f}{\partial x ^{2}} = - \frac{2}{81}

D (x, y) = - \frac{1}{2916}

Check the sign of at each critical point

Check critical point

(0, 0) :

Saddle

Saddle (0, 0)

25 - x^{2}

f (x) = - x^{3} + x^{2} - 9 x + 8

3 x^{3} + 30 x^{2} + 75 x - 9

f (x) = 2 x + 3200

f (x) = 2 x + \frac{8}{x ^{2}} + 1, x > 0

What is the extreme f(x)=(x^2)/(144)-(y^2)/(81) ?
The extreme f(x)=(x^2)/(144)-(y^2)/(81) is Saddle(0,0)