What is the critical 9x+7/x ?

The critical 9x+7/x is x=-(sqrt(7))/3 ,x=(sqrt(7))/3

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critical 9x+7/x

critical points

9 x + \frac{7}{x}

x = - \frac{7}{3}, x = \frac{7}{3}

Solution steps

9 x + \frac{7}{x}

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{7}{3}, x = \frac{7}{3}, x = 0

Identify critical points not in

f (x)

domain

Domain of

9 x + \frac{7}{x} : x < 0 or x > 0

9 x + \frac{7}{x}

is not defined at

x = 0

, therefore:

x = - \frac{7}{3}, x = \frac{7}{3}

f (x) = \frac{x + 2}{x ^{2} + 7 x + 10}

\frac{x}{4} + \frac{17}{4}

y = 4 x^{2} - x + 17

- x^{2} - 4, x \leq 0

f (x) = 8 x - 3 x^{2}

What is the critical 9x+7/x ?
The critical 9x+7/x is x=-(sqrt(7))/3 ,x=(sqrt(7))/3