What is the extreme f(x,y)=x^2-y^2-10x+2y+8 ?

The extreme f(x,y)=x^2-y^2-10x+2y+8 is Saddle(5,1)

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extreme f(x,y)=x^2-y^2-10x+2y+8

extreme points

f (x, y) = x^{2} - y^{2} - 10 x + 2 y + 8

Saddle (5, 1)

Solution steps

Find the critical points:

(5, 1)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 2

D (x, y) = - 4

Check the sign of at each critical point

Check critical point

(5, 1) :

Saddle

Saddle (5, 1)

f (x) = 9 - x^{2} es

- x^{2} + 4 x - 2

f (x) = x^{2} lo g_{10} (x)

f (x, y) = - x^{4} + 4 (x^{2} - y^{2}) - 3

f (x, y) = \frac{- x - ln ( x ^{2} + y ^{2} - 81 )}{666}

What is the extreme f(x,y)=x^2-y^2-10x+2y+8 ?
The extreme f(x,y)=x^2-y^2-10x+2y+8 is Saddle(5,1)