What is the extreme f(x)=2x^3-42x^2+270x+10 ?

The extreme f(x)=2x^3-42x^2+270x+10 is Maximum(5,560),Minimum(9,496)

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extreme f(x)=2x^3-42x^2+270x+10

extreme points

f (x) = 2 x^{3} - 42 x^{2} + 270 x + 10

Maximum (5, 560), Minimum (9, 496)

Solution steps

f^{'} (x) = 6 x^{2} - 84 x + 270

Find intervals:

Increasing

: - \infty < x < 5,

Decreasing

: 5 < x < 9,

Increasing

: 9 < x < \infty

Plug

x = 5

into

2 x^{3} - 42 x^{2} + 270 x + 10 : 560

Maximum (5, 560)

Plug

x = 9

into

2 x^{3} - 42 x^{2} + 270 x + 10 : 496

Minimum (9, 496)

Maximum (5, 560), Minimum (9, 496)

y = 6 x^{3} + 72 x^{2} + 270 x

\frac{( 4 x + 7 ) x + 9}{x ^{2} + 9 x}

f (x) = e^{(x^{2} - 2 x^{2} - 7 x)}

f (x) = x^{2} - 6 x - 3

\frac{d}{d x} (3 x a t [4.16])

What is the extreme f(x)=2x^3-42x^2+270x+10 ?
The extreme f(x)=2x^3-42x^2+270x+10 is Maximum(5,560),Minimum(9,496)