What is the extreme f(x)=e^{(x^2-2x^2-7x)} ?

The extreme f(x)=e^{(x^2-2x^2-7x)} is Maximum(-7/2 ,e^{49/4})

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extreme f(x)=e^{(x^2-2x^2-7x)}

extreme points

f (x) = e^{(x^{2} - 2 x^{2} - 7 x)}

Maximum (- \frac{7}{2}, e^{\frac{49}{4}})

Solution steps

f^{'} (x) = e^{- x^{2} - 7 x} (- 2 x - 7)

Find intervals:

Increasing

: - \infty < x < - \frac{7}{2},

Decreasing

: - \frac{7}{2} < x < \infty

Plug

x = - \frac{7}{2}

into

e^{x^{2} - 2 x^{2} - 7 x} : e^{\frac{49}{4}}

Maximum (- \frac{7}{2}, e^{\frac{49}{4}})

f (x) = x^{2} - 6 x - 3

\frac{d}{d x} (3 x a t [4.16])

- x^{3} + 27 x - 55

f (x, y) = x y (1 - 10 x - y)

f (x, y) = 9 - 3 y^{2} + 6 x^{2} - 2 y - 3 x^{3}

What is the extreme f(x)=e^{(x^2-2x^2-7x)} ?
The extreme f(x)=e^{(x^2-2x^2-7x)} is Maximum(-7/2 ,e^{49/4})