What is the extreme f(x)=-3x^3+9x^2-8 ?

The extreme f(x)=-3x^3+9x^2-8 is Minimum(0,-8),Maximum(2,4)

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extreme f(x)=-3x^3+9x^2-8

extreme points

f (x) = - 3 x^{3} + 9 x^{2} - 8

Minimum (0, - 8), Maximum (2, 4)

Solution steps

f^{'} (x) = - 9 x^{2} + 18 x

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < 2,

Decreasing

: 2 < x < \infty

Plug

x = 0

into

- 3 x^{3} + 9 x^{2} - 8 : - 8

Minimum (0, - 8)

Plug

x = 2

into

- 3 x^{3} + 9 x^{2} - 8 : 4

Maximum (2, 4)

Minimum (0, - 8), Maximum (2, 4)

f (x) = - 3 x^{3} + 9 x^{2} - 4

f (x, y) = x^{2} + y^{2} + 2 x - 6 y - 3

f (x y) = \frac{3 y + 5 x}{x y + 3}

f (x, y) = - 4 x^{2} + 8 x y - 2 y^{4} - 4

f (x) = \frac{2 ( - x + 1 )}{x ^{3}}

What is the extreme f(x)=-3x^3+9x^2-8 ?
The extreme f(x)=-3x^3+9x^2-8 is Minimum(0,-8),Maximum(2,4)