What is the extreme f(x)=(x^2*sqrt(y))/x ?

The extreme f(x)=(x^2*sqrt(y))/x is None

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extreme f(x)=(x^2*sqrt(y))/x

extreme points

f (x) = \frac{x ^{2} \cdot y}{x}

None

Solution steps

Find the critical points:

None

\frac{x ^{2} \cdot y}{x}

has no critical points, therefore there are no extreme points

None

f (x) = 2 x^{3} + 3 x^{2} - 120 x + 4, - 5 \leq x \leq 5

y = 4 (1.5)^{x}

x - 4 - 4

f (x) = 6 - (8 + 5 x)^{\frac{2}{5}}

f (x, y) = 3 x^{2} + 2 y^{2} - 4 y

What is the extreme f(x)=(x^2*sqrt(y))/x ?
The extreme f(x)=(x^2*sqrt(y))/x is None