What is the extreme ((x-1))/(e^{x+2)} ?

The extreme ((x-1))/(e^{x+2)} is Maximum(2, 1/(e^4))

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extreme ((x-1))/(e^{x+2)}

extreme points

\frac{( x - 1 )}{e ^{x + 2}}

Maximum (2, \frac{1}{e ^{4}})

Solution steps

f^{'} (x) = e^{- x - 2} (- x + 2)

Find intervals:

Increasing

: - \infty < x < 2,

Decreasing

: 2 < x < \infty

Plug

x = 2

into

\frac{x - 1}{e ^{x + 2}} : \frac{1}{e ^{4}}

Maximum (2, \frac{1}{e ^{4}})

14 + 14 x^{- \frac{3}{17}}

f (x, y) = x^{4} + 2 y^{2} - 8 x y

f (x) = x^{4} + y^{3} - 3 \cdot x^{2} + y^{2} + x - 2 \cdot y + 1

f (x) = \frac{x + 1}{x}

F (x) = \frac{- ( 160 x )}{( x ^{2} - 16 ) ^{2}}

What is the extreme ((x-1))/(e^{x+2)} ?
The extreme ((x-1))/(e^{x+2)} is Maximum(2, 1/(e^4))