What is the extreme f(x)=-15.4x^2+301.1x ?

The extreme f(x)=-15.4x^2+301.1x is Maximum(3011/308 ,1471.77288…)

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extreme f(x)=-15.4x^2+301.1x

extreme points

f (x) = - 15.4 x^{2} + 301.1 x

Maximum (\frac{3011}{308}, 1471.77288 \dots)

Solution steps

f^{'} (x) = - 30.8 x + 301.1

Find intervals:

Increasing

: - \infty < x < \frac{3011}{308},

Decreasing

: \frac{3011}{308} < x < \infty

Plug

x = \frac{3011}{308}

into

- 15.4 x^{2} + 301.1 x : 1471.77288 \dots

Maximum (\frac{3011}{308}, 1471.77288 \dots)

f (x) = - 3 x^{3} + 9 x^{2} + 10

f (x) = (x - y) (25 - x y)

f (x, y) = x^{2} y - 3 x y + 5 y

f (x, y) = e^{3 x^{2} + y^{2} + 6}

f (x) = x^{4} - 4 x + 7

What is the extreme f(x)=-15.4x^2+301.1x ?
The extreme f(x)=-15.4x^2+301.1x is Maximum(3011/308 ,1471.77288…)